The amount of Calcium hydroxide : = 58.719 g
Further explanation
Given
100 g Nitric Acid-HNO₃
Required
The amount of Calcium hydroxide
Solution
Reaction(balanced) :
Ca(OH)₂ (s) + 2HNO₃ (aq) → Ca(NO₃)₂ (aq) + 2H₂O (l)
mol of Nitric acid (MW 63 g/mol) :
mol = mass : MW
mol = 100 : 63
mol = 1.587
From the equation, mol ratio of Ca(OH)₂ : HNO₃ = 1 : 2, so mol Ca(OH)₂ :
=1/2 x mol HNO₃
= 1/2 x 1.587
=0.7935
Mass of Ca(OH)₂ (MW=74 g/mol) :
= mol x MW
= 0.7935 x 74
= 58.719 g
