Answer:
6.28 L
Explanation:
Given data:
Volume of NO₂ = ?
Mass of NO₂ = 12.9 g
Temperature and pressure = ?
Solution:
First of all we will calculate the number of moles of gas.
Number of moles = mass/molar mass
Number of moles = 12.9 g/ 46 g/mol
Number of moles = 0.28 mol
At standard temperature and pressure 1 mole of gas occupy 22.4 L volume.
Thus,
0.28 mol × 22.4 L/1 mol
6.27 L ≅ 6.28 L
