Answer:
P(x=4) = 0.4
Step-by-step explanation:
The density function of a continuous r.v is called a uniform distribution when between the end points any two sub intervals of the same length containing X, have the same probability.
f(x)= 1/ b-a a≤ x≤ b
Here a = 0 and b= 10 but we want to know the probability of wait time between 4 minutes and 10 minutes
P (X=x) = (x-a) 1/(b-a)
P(x=4) = (4-0) 1/ 10-0
= 4/10= 0.4
