livdoctor
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  • 18-12-2020
  • Mathematics
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7sin^2x+sinx-6=0

Does any one know the answer to this and how to solve???

Respuesta :

ashimsubedi67971161
ashimsubedi67971161 ashimsubedi67971161
  • 18-12-2020

Answer:

7Sin^2x+(7-6)sinx-6=0

7sin^2x+7sinx-6sinx-6=0

7sin(sinx+1)-6(sinx+1)=0

(sinx+1)(7sin-6)=0

either, or,

sinx+1=0 7sin-6=0

sinx=-1 sin=6/7

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