First you find the integral by using the property the integral of x^n (where n is a number) =(x^(n+1))/(n+1) So in this case: abs(x-5)=x^n (where n=1) - 5x^m (where m=0) so when you solve for it, you get =abs( [(x^(1+1))/ (1+1)] - [5(x^(0+1))/(0+1)] ) from 0 to 10 = abs( .5x^2 -5x) from 0 to 10 then plug in the top value, x=10, and subtract the bottom value, x=0, from it: =abs( .5(10^2) -5(10)) - abs(.5(0)-5(0)) =0 - 0 =0
