Answer:
Wavelength in water, [tex]\lambda=1.12\times 10^6\ m[/tex]
Explanation:
Given that,
A submarine uses sub-radio communication at 200 Hz.
The index of refraction, n = 1.333
The refractive index of a medium is given by :
[tex]\mu=\dfrac{c}{v}\\\\\mu=\dfrac{c}{\lambda_m f}\\\\\lambda_m=\dfrac{c}{\mu f}\\\\\lambda_m=\dfrac{3\times 10^8}{1.333\times 200}\\\\=1.12\times 10^6\ m[/tex]
So, the wavelength of the electromagnetic waves in water is [tex]1.12\times 10^6\ m[/tex].
