Answer: the value of the drain current ID is 3.56 mA
Explanation:
Given that;
IDSS = 8 mA
VP(VGS_OFF) = - 6 V.
VGS = - 2 V
value of the drain current ID = ?
Drain current ID is expressed as;
ID = IDSS [ 1 - (VGS/VP(VGS_OFF)) ]²
we substitute our value
ID = 8 [ 1 - (-2 / -6) ]²
ID = 8 [ 1 - 0.3333 ]²
ID = 8 [ 0.6667 ]²
ID = 8 [ 0.4444 ]
ID = 3.5552 ≈ 3.56 mA
Therefore the value of the drain current ID is 3.56 mA
