mariah2303 mariah2303
  • 16-12-2020
  • Mathematics
contestada

Find an equation of the line that passes through (3,10) and is parallel to the line x-3y=1

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altavistard
altavistard altavistard
  • 16-12-2020

Answer:

x - 3y = -27

Step-by-step explanation:

Two parallel lines have equations of the same form; only the constants differ.

Thus, if the given line is x - 3y = 1, the desired new line has equation of the form x - 3y = C, where we must find the value of C.

Substituting 3 for x and 10 for y in x - 3y = C, we get    3 - 3(10) = C, or

3 - 30 = C.  Thus, C = -27 and the desired new line is    x - 3y = -27.  

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vpu9wbkt9d vpu9wbkt9d
  • 17-12-2020
-27...............sidoofkendff
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