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If the equation px? +(p+1)x +p=0, has
equal roots, find values ofp. (WAEC)

Respuesta :

Juantai Juantai

16-12-2020

Answer:

1, -1/3

Explanation:

equal roots, so

b²-4ac=0

a=p b=p+1 c=p

(p+1)²-4(p)(p)=0

p²+2p+1-4p²=0

3p²-2p-1=0

(p-1)(3p+1)=0

p=1 or p=-1/3

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