The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
[tex]\frac{4C4\times48C9}{52C13}=0.00264106[/tex]
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
[tex]0.00264106\times13=0.0343[/tex]
The answer is 0.0343.
