Answer:
Let ΔABC and ΔDEF be two triangles such that ∠A = ∠D and ∠B = ∠E.
∠A + ∠B + ∠C = 180 0 (Sum of all angles in a Δ is 180)
∠D + ∠E + ∠F = 180 0 (Sum of all angles in a Δ is 180)
⇒ ∠A + ∠B + ∠C = ∠D + ∠E + ∠F
⇒ ∠D + ∠E + ∠C = ∠D + ∠E + ∠F (since ∠A = ∠D and ∠B = ∠E)
⇒ ∠C = ∠F
Thus the two triangles are equiangular and hence they are similar by AA.
Step-by-step explanation:
