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A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 8.0 times 10^1 N is being applied to the sled rope at an angle of 53 degrees to the grind, what is the force of friction between the sled and the snow?

Respuesta :

Answer:

48 Newtons

Explanation:

  • There is no acceleration and net forces.
  • [tex]8*10x^{-1} N cos(53) = friction[/tex]
  • Answer: 48.15 Newtons

The force of friction between the sled and the snow is 48 newtons.

Given that,

  • The force is [tex]8.0 \times 10^{1}[/tex].
  • N is being applied to the sled rope at an angle of 53 degrees to the grind.

Based on the above information, the calculation is as follows:

[tex]= 8\times 10x^{-1}N cos(53)[/tex]

= 48 newtons

Therefore we can conclude that the force of friction between the sled and the snow is 48 newtons.

Learn more: brainly.com/question/17127206