Answer:
565 kJ
Explanation:
[tex]H_v[/tex] = Heat of vaporization of water at 100°C = 2260 J/g
m = Mass of water = 250 g
Heat required is given by
[tex]Q=mH_v[/tex]
[tex]\Rightarrow Q=250\times 2260[/tex]
[tex]\Rightarrow Q=565000\ \text{J}[/tex]
[tex]\Rightarrow Q=565\times 10^3\ \text{J}[/tex]
[tex]\Rightarrow Q=565\ \text{kJ}[/tex]
The heat required to vaporize the water is 565 kJ.
