Answer:
0.0956 M
Explanation:
Step 1: Calculate the moles corresponding to 6.25 g of barium nitrate (solute)
The molar mass of barium nitrate is 261.34 g/mol.
6.25 g × 1 mol/261.34 g = 0.0239 mol
Step 2: Convert the volume of solution to liters
We will use the conversion factor 1 L = 1000 mL.
250 mL × 1 L/1000 mL = 0.250 L
Step 3: Calculate the molarity of the solution
The molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0239 mol / 0.250 L = 0.0956 M
