darling375
darling375 darling375
  • 19-10-2020
  • Mathematics
contestada

g(x)=2x^2+2x+21
Find g(p+4)​

gx2x22x21Find gp4 class=

Respuesta :

jimthompson5910 jimthompson5910
  • 21-10-2020

Answer:   2p^2 + 18p + 61

======================================================

Explanation:

Everywhere you see an x, replace it with p+4, then simplify.

We'll use the FOIL rule to expand out (p+4)^2

So...

g(x) = 2x^2 + 2x + 21

g(x) = 2( x )^2 + 2( x ) + 21

g(p+4) = 2( p+4 )^2 + 2( p+4 ) + 21 .... every x replaced with p+4

g(p+4) = 2(p^2+8p+16) + 2(p+4)+21 .... FOIL rule

g(p+4) = 2p^2+16p+32 + 2p+8+21 .... distribute

g(p+4) = 2p^2 + 18p + 61

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