abdtre5309
abdtre5309 abdtre5309
  • 19-10-2020
  • Mathematics
contestada

Solve for k: 4k+5a−3=10−2k

Solve for k 4k5a3102k class=

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Rosebasher
Rosebasher Rosebasher
  • 19-10-2020

Answer:

4k+5a_3=10_2k

4k+2k+5a=10+3

6k+5a=13

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