Respuesta :

WhiteAngel

The terms in which value of x when substituted leaves final value of p(x) = "0".

Here, x - 2 is factor. So value of x is 2.  

Substituting value of x we get,

p(x) = x3 - 3x + 5a

p(2) = 2*3 - 3(2) + 5a

0+ 8-6 + 5a

-2 = 5a

a= -0.4

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