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  • 18-10-2020
  • Mathematics
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How do you do this question?

How do you do this question class=

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MathPhys
MathPhys MathPhys
  • 18-10-2020

Answer:

Divergent

Step-by-step explanation:

an = 3 sin(2/n)

Choose bn = 3 (2/n).

Using Limit Comparison Test:

lim(n→∞) an / bn

= lim(n→∞) [3 sin(2/n)] / [3 (2/n)]

= lim(n→∞) [sin(2/n)] / (2/n)

= 1

The limit is greater than 0, and bn diverges, so an also diverges.

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