abiigaiilx
abiigaiilx abiigaiilx
  • 19-09-2016
  • Mathematics
contestada

What is 4 over 9, to the power of negative a half? - Can you also give an
explanation of how to do it?

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MathGeek289
MathGeek289 MathGeek289
  • 21-09-2016
So, We Have:
[tex] (\frac{4}{9}) ^{ (-\frac{1}{2}) } [/tex]
We Know that Negative Exponents Equal Division.  So:[tex] \frac{4}{9}^{( -\frac{1}{2} )} = \frac{1}{ \sqrt[]{ \frac{4}{9} } } = \frac{1}{ (\frac{2}{3} )} = \frac{3}{2} = 1.5[/tex]
I Hope This Helps!

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