Rickyhuff Rickyhuff
  • 18-09-2016
  • Mathematics
contestada

What are the intercepts of x^4-2x^2-8

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helpme521
helpme521 helpme521
  • 18-09-2016
You need it to equal something or it does not make sense
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caylus
caylus caylus
  • 18-09-2016
Hello,

For axis x:
[tex]x^4-2x^2-8=0 \\ ==\textgreater\ (x^2)^2-2(x^2)-8=0\\ \Delta=4+4*8=36=6^2 \\0 ==\textgreater\ x^2= \dfrac{2+6}{2}\ or \ x^2= \dfrac{2-6}{2}(negative\ to \ refute) \\ ==\textgreater \ x^2=4\\ ==\textgreater \ (x-2)(x+2)=0\\ [/tex]

For axis y:
x=0==>y=-8



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