michael82012 michael82012

19-09-2020
Mathematics

contestada

Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5

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officialstephhk officialstephhk

19-09-2020

Answer:

[tex]2a^3b^4(8b^3+a^3-11ab)[/tex]

Step-by-step explanation:

[tex]as^3b^4(8b^3) +2a^6b^4-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3-11ab)[/tex]

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