Answer:
Nitrogen 13
Explanation:
We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.
[tex]X\rightarrow ^0e_1+^{13}C_6[/tex]
In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,
[tex]^{13}_7 N \rightarrow ^0e_1+^{13}C_6[/tex]
So, the LHS have nitrogen 13, a radioactive isotope.
