Answer:
a = √157
b = √85
First Question
To find a we Pythagoras theorem
That's
[tex] {a}^{2} = {6}^{2} + {11}^{2} \\ {a}^{2} = 36 + 121 \\ \\ {a}^{2} = 157 \\ \\ a = \sqrt{157} \\ [/tex]
Second question
[tex] {11}^{2} = {b}^{2} + {6}^{2} \\ \\ {b}^{2} = 121 - 36 \\ \\ {b}^{2} = 85 \\ \\ \\ b = \sqrt{85} [/tex]
Hope this helps you
