Answer:
B and D are correct
Step-by-step explanation:
Hello,
to find the zeroes we need to solve y = 0
so D is correct
and we can write
[tex]-5(x-4)^2+10=0\\<=>5(x-4)^2=10\\<=> (x-4)^2=10/5=2\\<=> x-4=\sqrt{2} \ or \ x-4=-\sqrt{2}\\<=> x=4+\sqrt{2} \ \ or \ \ x=4-\sqrt{2}[/tex]
so B is correct
hope this helps
