Answer:
Step-by-step explanation:
[tex](x-3)^2=49[/tex]
<=>
[tex](x-3)^2-49=0\\\\<=> (x-3)^2-7^2=0\\\\<=> (x-3-7)(x-3+7)=0\\<=> (x-10)(x+4)=0\\<=> x -10=0\ or \ x+4=0\\<=> x = 10 \ or\ x = -4[/tex]
solutions are -4 and 10
do not hesitate if you need further explanation
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