Respuesta :

bharatkhadka7777

Step-by-step explanation:

64y^2+(16-12)y-3

=64y^2+16y-12y-3

=16y(4y+1)-3(4y+1)

=(16y-3) (4y+1)

RyGuy033

Answer: [tex](16y-3)(4y+1)\\[/tex]

Step-by-step explanation:

[tex]64y^{2}+4y-3[/tex]

[tex]64y^{2}+16y-12y-3[/tex]

[tex](64y^{2}+16y)+(-12y-3)[/tex]

[tex]16y(4y+1)-3(4y+1)\\[/tex]

[tex](16y-3)(4y+1)\\[/tex]

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