Answer:
Step-by-step explanation:
y = 3x - 5
m₁ = 3
The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂
m₂ = -1/m₁
m₂ = -1/3
Point (9,6)
Equation of line: y - y₁ = m(x - x₁)
y - 6 = (-1/3)(x - 9)
[tex]y-6=\frac{-1}{3})x+\frac{1}{3}*9\\\\y-6=\frac{-1}{3}x+3\\\\y=\frac{-1}{3}x+3+6\\\\y=\frac{-1}{3}x+9\\[/tex]
