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16-06-2020
Mathematics

contestada

r=p/4(c+k) for k, please help, thank you!

Respuesta :

09pqr4sT 09pqr4sT

16-06-2020

Answer:

[tex]k=\frac{-cp+4r}{p}[/tex]

Step-by-step explanation:

[tex]r=p/4(c+k)[/tex]

[tex]\frac{r}{p/4} =c+k[/tex]

[tex]\frac{r}{p/4} -c=k[/tex]

[tex]-cp+4r=kp[/tex]

[tex]\frac{-cp+4r}{p} =k[/tex]

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