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  • 19-05-2020
  • Mathematics
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2 ( n-1 ) + 4n= 2( 3n-1 )

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 19-05-2020

Answer:

infinite solutions

Step-by-step explanation:

2 ( n-1 ) + 4n= 2( 3n-1 )

Distribute

2n -2 +4n = 6n -2

Combine like terms

6n -2 = 6n -2

Subtract 6n from each side

6n-2-6n = 6n-2-6n

-2 = -2

This is always true so there are infinite solutions

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