jak7ha2Girlbellacno jak7ha2Girlbellacno

19-08-2016
Mathematics

contestada

in ∆abc, what is the value of cos b?

Respuesta :

dalendrk dalendrk

21-08-2016

[tex]c^2=a^2+b^2-2ab\cos\beta\\\\2ab\cos\beta=a^2+b^2-c^2\\\\\boxed{\cos\beta=\dfrac{a^2+b^2-c^2}{2ab}}[/tex]

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