EsquivaldoVanJorgen EsquivaldoVanJorgen

19-04-2020
Computers and Technology

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Para una fibra óptica con índice n1=1,5 y una cubierta de índice n2=1,4 ¿cuál es su apertura numérica?

For an optical fiber with index n1 = 1.5 and a cover with index n2 = 1.4, what is its numerical aperture?

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20-04-2020

Answer:

[tex]0.54[/tex]

Explanation:

[tex]NA=\sqrt{n_1^2-n_2^2}[/tex]

Substitute known values

[tex]NA=\sqrt{1.5^2-1.4^2}=\sqrt{0.29} = 0.54[/tex]

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