Answer:
Below in BOLD.
Step-by-step explanation:
h(t) = -0.2t^2 + 2t
We can find the maximum height and the time by converting to vertex form:
h(t) = -0.2(t^2 - 2t)
= -0.2[(t - 1)^2 - 1)
= -0.2(t - 1)^2 + 0.2
The time to get to maximum height = 1 second and the maximum height is 0.2 m.
When the ball reaches the ground h = 0 so
-0.2(t - 1)^2 + 0.2 = 0
(t - 1)^2 = -0.2 / -0.2 = 1
t - 1 = 1
t = 2 seconds.
