Answer:
Force between two charges is given as 143.3 N
Explanation:
As we know that electrostatic force between two point charges is given as
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
here we know that
[tex]q_1 = -5.3 \mu C[/tex]
[tex]q_2 = 5.3 \mu C[/tex]
also we know that
[tex]r = 4.2 cm[/tex]
so we have
[tex]F = \frac{(9\times 10^9)(5.3 \times 10^{-6})(5.3\times 10^{-6})}{0.042^2}[/tex]
so we have
[tex]F = 143.3 N[/tex]
