Answer:
Let's simplify step-by-step.
(−a)(−4 − 5a) − 3a(2 + a)
Distribute:
= (−a)(−4) + (−a)(−5a) + −3a^2 + −6a
= 4a + 5a^2 + −3a^2 + −6a
Combine Like Terms:
= 4a+5a^2 + −3a^2+ −6a
= (5a2+ −3a^2) + (4a + −6a)
= 2a2 + −2a
Final Answer:
= 2a^2−2a!
Answer:
a = 0 or a = 1
Step-by-step explanation:
-a(-4 - 5a) - 3a(2 + a) = 0
4a + 5a² - 6a - 3a² = 0
2a² - 2a = 0
2a(a - 1) = 0
2a = 0
a = 0
Or
a - 1 = 0
a - 1 + 1 = 0 + 1
a = 1
Note that a quadratic equation always has two solutions.
