Answer:
55.15 sec.
Explanation:
Given that the force = [tex]1.50\times 10^3[/tex] N
We know, Force = mass × acceleration
So,
Acceleration = [tex]\frac{Force}{Mass}= \frac{1.50\times10^3}{1.550\times10^4} = 0.097 ms^-^2[/tex] is the negative acceleration produced by the force.
Now, using formula [tex]v=u-at[/tex]
As the car finally stops so [tex]v[/tex] will be zero.
So,
[tex]0=5.35-0.097\times t[/tex]
Thus, [tex]t= \frac{5.35}{0.097}[/tex] = 55.15 sec.
So, the time required for the force to bring the car to rest will be 55.15 seconds.
