A student figures that he has a 4141% chance of being let out of class late. If he leaves class late, there is a 3030% chance that he will miss his train. What is the probability that he gets out of class late and misses the train?

In this case, despite being different events, they are dependent on each other, therefore the final probability would be the multiplication of both probabilities.

So let L be the probability of being late that is equal to 41% and let T be the probability that the train will leave you and is equal to 30%.

That is to say:

L = 41% = 0.41

T = 30% = 0.3

So:

P = L * T

P = 0.41 * 0.3 = 0.123

So it means that the final probability is 12.3%

A student figures that he has a 4141​% chance of being let out of class late. If he leaves class​ late, there is a 3030​% chance that he will miss his train. What is the probability that he gets out of class late and misses the​ train?

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A student figures that he has a 4141% chance of being let out of class late. If he leaves class late, there is a 3030% chance that he will miss his train. What is the probability that he gets out of class late and misses the train?