Answer:
[tex]\omega = 1.914\ rad/s[/tex]
Explanation:
Given,
Number of turns, N = 645 N
Area, A = 20.25 m²
Earth Magnetic field, B = 5 x 10⁻⁵ T
Maximum Emf = 1.25 V.
Angular velocity, ω = ?
Using Induced Emf formula
[tex]\varepsilon = NAB\omega[/tex]
[tex]\omega= \dfrac{\varepsilon}{NAB}[/tex]
[tex]\omega= \dfrac{1.25}{645\times 20.25\times 5\times 10^{-5}}[/tex]
[tex]\omega = 1.914\ rad/s[/tex]
Angular velocity of the coil = [tex]\omega = 1.914\ rad/s[/tex]
