sierraparis409 sierraparis409
  • 16-03-2020
  • Physics
contestada

10N force isn’t applied to a hockey puck over a period of 0.1s. What is the change in momentum of the hockey puck

Respuesta :

blarvind blarvind
  • 17-03-2020

Answer:

[tex]\Delta p = 1.0 \ \rm N.s[/tex]

Explanation:

Given data:

Force, [tex]F = 10 \ \rm N[/tex]

Time period, [tex]t = 0.1 \ s[/tex]

The change in momentum experienced by the puck can be given as,

[tex]\Delta p = F \times t[/tex]

[tex]\Delta p = 10 \ \rm N \times 0.1 \ s[/tex]

[tex]\Delta p = 1.0 \ \rm N.s[/tex]

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