williamdford99 williamdford99
  • 20-02-2020
  • Physics
contestada

A 5.5 kg box is pushed across the lunch table. the net force applied to box is 9.7 N. what is the acceleration of the box?

Respuesta :

Onoriodefelix
Onoriodefelix Onoriodefelix
  • 20-02-2020

Answer:

a = 1.76m/s^2

Explanation:

Force = mass x acceleration

F = m x a

N = kg x m/s^2

From the question

m = 5.5kg

F = 9.7N

Therefore,

Using the above formula

9.7 = 5.5 x a

9.7 = 5.5a

Divide both sides by 5.5

9.7/5.5 = 5.5a/5.5

1.76 = a

a = 1.76m/s^2

Answer Link
michellecarrascono2
michellecarrascono2 michellecarrascono2
  • 12-01-2021

Answer:it’s 1.76m/s^2

Explanation:

Right

Answer Link

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