Respuesta :

ajeigbeibraheem

Answer:

4.8 kcal/g

Explanation:

Given that:

mass of water = 50 g = 0.05 kg

specific heat capacity of water (c)= 1 kcal/K.kg

changes in temperature ΔT = 42°C - 18°C = 24°C

Since q = mcΔT

q = 0.05 × 1 × 24

q = 1.2 kcal

∴ 0.25 g sample of pretzel give 1.2 kcal of heat

as such 1 g of the sample will give out:

[tex]\frac{1}{0.25}*1.2[/tex]

= 4.8 kcal/g

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