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Is −8c an even integer? Yes, because −8c = 2(−4c) + 1 and −4c is an integer. Yes, because −8c = 2(−4c) and −4c is an integer. No, because −8c = 2(−4c) and −4c is an integer. No, because −8c = 2(−4c) + 1 and −4c is an integer.

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Answer:

Yes, because −8c = 2(−4c) and −4c is an integer

Step-by-step explanation:

We want to determine whether [tex]-8c[/tex] is an even integer.

Recall that even integers are of the form: [tex]2n[/tex]

Let us see if we can rewrite the given expression in the form 2n, where n is an integer.

Let us factor 2 to get:

[tex]-8c=2(-4c)[/tex]

If -4c is an integer and we let m=-4c,then

[tex]-8c=2(m)=2m[/tex], where m is an integer.

Therefore the answer is Yes, because −8c = 2(−4c) and −4c is an integer

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