Answer:
A
Step-by-step explanation:
[tex]\frac{\frac{y^2+y}{y^2-2y} }{\frac{4y+4}{y^2-4y+4} } \\=\frac{y^2+y}{y^2-2y} *\frac{y^2-4y+4}{4y+4} \\=\frac{y(y+1)}{y(y-2)} *\frac{y^2-2y-2y+4}{4(y+1)} \\=\frac{y(y+1)}{y(y-2)} *\frac{y(y-2)-2(y-2)}{4(y+1)} \\=\frac{y(y+1)}{y(y-2)} *\frac{(y-2)(y-2)}{4(y+1)}[/tex]
