blackoak7994 blackoak7994
  • 21-01-2020
  • Physics
contestada

It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. Find the spring constant k.

Respuesta :

Vespertilio Vespertilio
  • 22-01-2020

Answer:

212.5 N/m

Explanation:

Work, W = 1700 J

y1 = 2 m

y2 = 6 m

y = y2 - y1 = 6 - 2 = 4 m

Let K be the spring constant.

Work done is given by

W = 1/2 Ky²

1700 = 0.5 x K x 4 x 4

K = 212.5 N/m

Thus, the spring constant is given by 212.5 N/m.

Answer Link

Otras preguntas

What best describes the solution 0=15?
The length of a rectangle is 3 inches more than its width, and its perimeter is 22 inches. Find the width of the rectangle
what is the slope and y-intercept for y=7/3x+5
What does biodiversity mean
What is the charge of the nucleus of an oxygen atom? 0 –2 +8 +16
In the equation 3^x=20, to the nearest tenth, what does x equal?
what are the most common reasons for mispronunciation?
could you tell me what Is a Shiksa?
the product of 8 and a number x is equal to 32. write an algebraic expression, an equation, or an inequality
what would the answer be? 619-(68+q) and q is 386