Answer:
[tex]\frac{I_{2}}{I_{1}} = 10^{0.1}[/tex]
Explanation:
The sound intensity level β can be mathematically defined as
[tex]\beta(dB) = 10log_{10}(\frac{I}{I_{o} } )[/tex]
where [tex]I_{o}[/tex] is the reference intensity and is equal to [tex]10^{-12}[/tex] [tex]W/m^{2}[/tex].
Now,
[tex]\beta_{2} - \beta_{1} = 10 log\frac{I_{2} }{I_{o}} - 10 log\frac{I_{1} }{I_{o}}\\62-60= 10log(\frac{\frac{I_{2} }{I_{o} } }{\frac{I_{1} }{I_{o} } } )\\1=10log(\frac{I_{2} }{I_{1} } )\\\\\frac{I_{2} }{I_{1} }=10^{0.1}[/tex]
