tiannasmi23 tiannasmi23
  • 21-01-2020
  • Mathematics
contestada

2b^2x^2+3a^2y^2=a^2b^2 for b^2

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 02-02-2020

Answer:

[tex]{b}^{2} = \frac{3 {a}^{2} {y}^{2} }{ {a}^{2} - 2 {x}^{2} } [/tex]

Step-by-step explanation:

We want to solve for b² in

[tex]2 {b}^{2} {x}^{2} + 3 {a}^{2} {y}^{2} = {a}^{2} {b}^{2} [/tex]

Combine terms containing b²

[tex]3 {a}^{2} {y}^{2} = {a}^{2} {b}^{2} - 2 {b}^{2} {x}^{2}[/tex]

Factor b² to get:

[tex]3 {a}^{2} {y}^{2} = ({a}^{2} - 2 {x}^{2}) {b}^{2} [/tex]

Divide by a² -2b²

[tex] {b}^{2} = \frac{3 {a}^{2} {y}^{2} }{ {a}^{2} - 2 {x}^{2} } [/tex]

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