Answer:
10.21°C
Explanation:
From the question,we are given;
- Quantity of heat = 32,000 Joules
- Mass of water = 750 g
- Specific heat capacity of water = 4.18 J/g°C
We are required to calculate the change in temperature;
- We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
- That is;
Q = m × c × ΔT
Rearranging the formula;
ΔT = (Q ÷ (m × c))
= 32,000 J ÷ (750× 4.18 J/g°C)
= 10.21°C
Therefore, the change in temperature is 10.21°C
