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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reaction:
PCl3 (g) + Cl2 (g) → PCl5 (g)
An equilibrium mixture at 450 K contains PPCl3 = 0.124 atm, PCl2 = 0.157 atm, and PPCl5 = 1.30 atm.

What is the value of Kp at this temperature?

Respuesta :

abdullahjawaid1

Answer:

Kp = 67

Explanation:

The reaction is given as:

PCl3 (g) + Cl2 (g) → PCl5 (g)

Now, the Kp expression at equilibrium for this reaction is written as:

[tex]Kp = (PPCl5) / (PPCl3)(PCl2)[/tex]

[tex]Kp = (1.30) / (0.124)(0.157)[/tex]

[tex]Kp = 67[/tex]

Notes:

  1. Kp is the gas constant at equilibrium in terms of partial pressures of gas.
  2. For a reaction: aA + bB <===> cC +dD, the expression of Kp can be written as:

[tex]Kp = (PC)^{c}.(PD)^{d} / (PA)^{a}. (PB)^{b}[/tex]

Answer:

kp will be 67

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