Answer:
a) P=0.84
b) Mean=0.33
Standard deviation=0.356
Step-by-step explanation:
The probabilty that the measurement error in a randomly selected instance us less than 0.6 µs is P=0.84.
The mean of a Beta(α = 1, β = 2) is
[tex]\mu=\frac{\alpha}{\alpha+\beta}=\frac{1}{1+2}=0.33[/tex]
The standard deviation of a Beta(α = 1, β = 2) is
[tex]\sigma=\sqrt{\frac{\alpha\beta}{(\alpha+\beta)^2*(\alpha+\beta+1)}}\\\\\\\sigma= \sqrt{\frac{1*2}{(1+2)^2*(1+2+1)}}=\sqrt{\frac{2}{(2)^2*(4)}}=\sqrt{\frac{2}{16} } =\sqrt{0.125}= 0.356[/tex]
