leahstubbs leahstubbs
  • 18-12-2019
  • Mathematics
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Given: LN⊥KM,KL≅ML Prove: ΔKLN≅ΔMLN

Given LNKMKLML Prove ΔKLNΔMLN class=

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inchu420 inchu420
  • 26-12-2019

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

LN⊥KM,

KL≅ML

To Prove:

ΔKLN≅ΔMLN

Proof:

In  Δ KLN and Δ MLN

KL ≅ ML     ....……….{Given i.e Hypotenuse }

LN ≅ LN     …………..{Reflexive Property}

∠ LNK ≅ ∠ LNM  ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}

Δ KLN ≅ Δ MLN     ….{By Hypotenuse Leg Theorem} ....Proved

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