Answer:
y = - 10 and x = 5
Step-by-step explanation:
[tex] - 9x - 6y = 15 \\ + 9x - 10y = + 145 \\ add \: the \: two \: equations \: together \\ 0 - 16y = 160 \\ y = \frac{160}{ - 16} \\ y = - 10 \\ substitute \: for \: y\: in \: any \: equation \\ - 9x - 6( - 10) = 15 \\ - 9x + 60 = 15 \\ - 9x = 15 - 60 \\ - 9x = - 45 \\ x = \frac{ - 45}{ - 9} \\ x = 5[/tex]
